invalid static_cast from type 'void* to type 'int

For example: 1. Because widening conversions are always safe, the compiler performs them silently and doesn't issue warnings. Here, the data type is the type of data that we type case, For example, we can convert Integer type to Short type. When we add up these two variables, an implicit conversion takes place. The static_­cast operator shall not cast away constness. This is pretty low level stuff, and I'm not too familiar with this. You are only going to hurt you C++ code by using design strategies meant for C. edit: static_cast should be used for casting void* to typed pointers according to Effective C++. Invalid Cast AsEnumberable() - social.msdn.microsoft.com How to correctly type cast (void*)? - social.msdn.microsoft.com resolving "invalid conversion from 'byte* {aka unsigned char*}' to ... result = (T)(Int64)value; But I cannot do this in the generic method. The reinterpret_cast<> must be used carefully. This is also the cast responsible for implicit type coercion and can also be called explicitly. What Exactly Nullptr Is in C++? - DZone Web Dev static_cast in C++ | Type Casting operators - GeeksforGeeks Pattern 7. You should use it in cases like converting float to int, char to int, etc. When using malloc / free in C++, you have to cast the void* pointer as returned by malloc to your desired pointer type: FullList = static_cast<int*> (malloc (N * sizeof (int))); l = static_cast<int*> (malloc (N * sizeof (int))); The reason for this (when simply copying over C code) is that in C these casts are allowed to be performed implicitly . static_cast in C++ - Tutorials Point

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